RSA Algorithm Example
- Choose p = 3 and q = 11
- Compute n = p * q = 3 * 11 = 33
- Compute φ(n) = (p - 1) * (q - 1) = 2 * 10 = 20
- Choose e such that 1 < e < φ(n) and e and n are coprime. Let e = 7
- Compute a value for d such that (d * e) % φ(n) = 1. One solution is d = 3 [(3 * 7) % 20 = 1]
- Public key is (e, n) => (7, 33)
- Private key is (d, n) => (3, 33)
- The encryption of m = 2 is c = 27 % 33 = 29
- The decryption of c = 29 is m = 293 % 33 = 2
1 comments:
sir i got that and it was very much simplfied by you, but can you please illustrate me the theory behind RSA ?
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